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7 June, 05:55

A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is moving at a velocity of - 7 m/s. After colliding, the 35-gram ball moves at a velocity of - 15 m/s. Assume there is no net force on the system. What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth. - 4.2 m/s - 0.5 m/s 0.5 m/s 4.2 m/s

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  1. 7 June, 09:38
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    Option D is the correct answer.

    Explanation:

    The given figure shows the arrangement

    We have momentum is conserved before and after collision.

    Momentum before collision

    = 35 * 9 + 75 * (-7) = - 210 g m/s

    Momentum after collision

    = 35 * (-15) + 75 * V = 75 V - 525

    V is the velocity of 75 g ball after collision.

    We have momentum conservation equation

    So, - 210 = 75 V - 525

    75 V = 525 - 210 = 315

    V = 4.2 m/s

    So velocity of 75 g ball is 4.2 m/s.

    Option D is the correct answer.
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