A length change 0.08 m will occur for an object that is L = 56 m long. If the coefficient of thermal expansion is5.3 x 10 / C and if the original temperature is 253 C, find the increase in temperature.

Increase in temperature = 269.54 °C

Explanation:

We have equation for thermal expansion

ΔL = LαΔT

Change in length, ΔL = 0.08 m

Length, L = 56 m

Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1

Change in temperature, ΔT = T - 253

Substituting

0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)

(T - 253) = 269.54

T = 522.54 °C

Increase in temperature = 269.54 °C