Ask Question
17 August, 02:20

A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, the gravitational acceleration (g) is 9.8 m/s2. (Hint: d = ½gt2)

+3
Answers (1)
  1. 17 August, 03:45
    0
    consider the motion of the bowling ball along the vertical direction after it is thrown off.

    assuming down direction as positive.

    Y = vertical displacement of the bowling ball = distance traveled downward = d

    a = acceleration of the ball = acceleration due to gravity = 9.8 m/s²

    t = time of travel = 3.0 s

    v₀ = initial velocity of the ball along the vertical direction = 0 m/s

    using the equation

    Y = v₀ t + (0.5) a t²

    d = 0 (3.0) + (0.5) (9.8) (3.0) ²

    d = (0.5) (9.8) (9.0)

    d = 44.1 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers