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15 March, 12:39

An object of weight 8N is moving along a horizontal plane. If the coefficient of kinetic friction is 0.25 find the friction force acting on the object.

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  1. 15 March, 13:40
    0
    2 N

    Explanation:

    Wight of object = mg = 8 N

    Coefficient of friction, u = 0.25

    The normal reaction acting on the object = N = mg = 8 N

    According to the laws of limiting friction,

    The friction force, f = uN

    f = 0.25 x 8 = 2 N
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