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11 March, 05:18

An aluminium pot whose thermal conductivity is 237 W/m. K has a flat, circular bottom

with diameter 15 cm and thickness 0.4 cm. Heat is transferred steadily to boiling water in

the pot through its bottom at a rate of 1400 W. If the inner surface of the bottom of the pot

is at 105 °C, determine the temperature at the outer surface of the bottom of the pot

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Answers (1)
  1. 11 March, 05:53
    0
    T₁ = 378.33 k = 105.33°C

    Explanation:

    From Fourier's Law of heat conduction, we know that:

    Q = - KAΔT/t

    where,

    Q = Heat Transfer Rate = 1400 W

    K = Thermal Conductivity of Material (Aluminum) = 237 W/m. k

    A = Surface Area through which heat transfer is taking place=circular bottom

    A = π (radius) ² = π (0.15 m) ² = 0.0707 m²

    ΔT = Difference in Temperature of both sides of surface = T₂ - T₁

    T₁ = Temperature of outer surface = ?

    T₂ = Temperature of inner surface = 105°C + 273 = 378 k

    ΔT = 388 k - T₁

    t = thickness of the surface (Bottom of Pot) = 0.4 cm = 0.004 m

    Therefore,

    1400 W = - (237 W/m. k) (0.0707 m²) (378 k - T₁) / 0.004 m

    (1400 W) / (4188.14 W/k) = - (378 k - T₁)

    T₁ = 0.33 k + 378 k

    T₁ = 378.33 k = 105.33°C
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