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16 August, 23:40

Jon pushes a lawnmower with a force of 50.0 N directed at 50 degrees from the horizontal. The lawn mower moves 90.0 m. If Jon took 10.0 minutes to mow 90.0 m of grass, what was his power in SI units?

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  1. 17 August, 01:40
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    F = force by which Jon pushes the lawnmower = 50.0 N

    θ = Angle of the force applied with the horizontal = 50 degrees

    d = displacement of the lawnmower due to force applied = 90.0

    W = work done on the lawnmower = ?

    work done on the lawnmower is given as

    W = F d Cosθ

    inserting the values

    W = (50.0) (90.0) Cos50

    W = (4500) Cos50

    W = 2892.54 J

    t = time taken by Jon to mow the lawnmower = 10.0 minutes = 10.0 x 60 sec = 600 sec (Since 1 min = 60 sec)

    Power is given as

    P = W/t

    inserting the values in the above formula

    P = 2892.54/600

    P = 4.82 Watt
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