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19 November, 15:08

During a volleyball serve, the ball leaves the hand with an initial velocity of 10 m/s angled 41 degrees from the horizontal. What are the horizontal and vertical velocities of the ball?

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  1. 19 November, 18:38
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    7.55 m/s, 6.56 m/s

    Explanation:

    v = 10 m/s, theta = 41 degree

    Horizontal component of velocity = v x Cos theta = 10 x Cos 41 = 7.55 m/s

    Vertical component of velocity = v x Sin theta = 10 x Sin 41 = 6.56 m/s
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