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17 May, 17:57

the specific heat of water is 4.186. suppose 100 J of heat is added to a body of water that is insulated and the temperature rose 1 degrees Celsius. how much mass of water is the body of water?

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Answers (2)
  1. 17 May, 20:40
    0
    Givens

    m=? c = 4.186 deltaT = 1 degree C Heat = 100 J

    Formula

    Heat = m*c*ΔT

    Solution

    100 = m * 4.186 * 1 100 = 4.186 * m 100/4.186 = m m = 23.889 Answer
  2. 17 May, 21:43
    0
    C = ms

    Delta H = ms * delta T

    100=m*4.186*1

    m=100/4.184=23.9 g
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