Ask Question
21 August, 03:02

What is the capacitance of a parallel place capacitor with plates of area 1.0 cm2 that are separated by a distance of 0.1 mm? Assume that strontium titanate is the dielectric.

+3
Answers (1)
  1. 21 August, 04:29
    0
    C = 0.274μF.

    The capacitance when a dielectric is present is given by the equation:

    C = kε₀ (A/d)

    Where k is the dielectric constant of the material, ε₀ is a universal constant, A is the area of the capacitor's plates, and d is the distance that separate the plates.

    A parallel plates capacitor with plates of area 1.0cm² that are separated by a distance of 0.1mm, the dielectric constant of the stronium titanate is 310 at a temperature of 20 ° C.

    K = 310.00, ε₀ = 8.85x10⁻¹²F/m, A = 1.00x10⁻²m², and d = 0.10x10⁻³m. Substituing the values in the equation C = kε₀ (A/d):

    C = (310.00) (8.85x10⁻¹²F/m) (1.00x10⁻²m²/0.10x10⁻³m)

    C = (2.74x10⁻⁹F/m) (100m)

    C = 2.74x10⁻⁷F

    C = 0.274x10⁻⁶ = 0.274μF
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the capacitance of a parallel place capacitor with plates of area 1.0 cm2 that are separated by a distance of 0.1 mm? Assume that ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers