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6 September, 11:05

a cricket ball of 70g moving with a velocity of 0.5 m/s is stopped by a player in 0.5s what is the force applied to stop the ball

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  1. 6 September, 14:12
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    Force = change in momentum / impact time

    = mass (change in velocity) / impact time

    = 0.07 (0.5-0) / 0.5

    = 0.07N
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