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28 June, 16:52

A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.

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  1. 28 June, 19:54
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    b) 20 kJ

    Explanation:

    Efficiency of carnot engine = (T₁ - T₂) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink.

    T₁ = 270 + 273 = 543K

    T₂ = 50 + 273 = 323 K

    Putting the given values of temperatures

    efficiency = (543 - 323) / 543

    =.405

    heat input = 50 KJ

    efficiency = output work / input heat energy

    .405 = output work / 50

    output work = 20.25 KJ.

    = 20 KJ.
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