Three sleds are being pulled horizontally on frictionless horizontal ice using horizontal ropes (Fig. 5.48). The pull is horizontal and of magnitude 125 N. Find (a) the acceleration of the system and (b) the tension in ropes A and B.

acceleration=2.0833 m/s^2

Tension in rope A=104.167 N

Tension in rope B=62.5 N

Explanation

mass of sleds are 10,20 and 30 Kg respectively.

Total mass = 60 kg

F=ma

a=f/m

f=125 N

a=125/60

a=2.0833 m/s^2

Now using equation of equilibrium

F-Ta=ma*a

Ta=F-ma*a

Ta=125 - (10*2.0833)

Ta=104.167 N

Tb=mc*a

Tb=30*2.0833

Tb=62.5 N