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7 August, 11:17

Two parallel wires are separated by 6.65 cm, each carrying 3.25 A of current in the same direction. (a) What is the magnitude of the force per unit length between the wires?

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  1. 7 August, 11:24
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    The magnitude of the force per unit of lenght between the wires are of F/L = 3.17 * 10⁻⁵ N/m.

    Explanation:

    d=0.0665m

    I1=I2 = 3.25A

    μo = 4π * 10⁻⁷ N/A²

    F/L = (μo * I1 * I2) / (2π * d)

    F/L = 3.17 * 10⁻⁵ N/m
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