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30 March, 22:42

An orange of mass 3kg falls from a height 50m. When its height is H, its speed is

4m/s?

Write an expression that describes the conservation of energy with the given

numbers and H. You don't have to solve for H.

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Answers (1)
  1. 30 March, 23:51
    0
    (10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s) ²

    Explanation:

    Initially, the orange has only gravitational potential energy.

    As the orange falls, it has a combination of potential energy and kinetic energy.

    Energy is conserved, so initial energy = final energy:

    PE₀ = PE + KE

    mgH₀ = mgH + ½ mv²

    gH₀ = gH + ½ v²

    Plugging in values:

    (10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s) ²
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