A rock is dropped from a height of 2.5 meters. What is its velocity when it reaches the ground?

The velocity of the rock when it reaches the ground is

7

m

s

.

Explanation:

The formula we are using is

V

2

2

=

V

2

1

+

2

a

Δ

d

=> Where

V

is the velocity in

m

s

.

=> Where

a

is acceleration in

m

s

2

.

=> Where

Δ

d

is the change in displacement in

m

.

So now we just plug in the numbers.

V

2

2

=

V

2

1

+

2

a

Δ

d

=

0

+

2

(

9.8

)

(

2.5

)

=

√

49

=

7

The velocity of the rock when it reaches the ground is

7

m

s

.