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30 June, 20:21

A 3.00-kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2. Find (a) the resultant force acting on the object and (b) the magnitude of the resultant force.

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  1. 30 June, 22:49
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    (a) : The resultant force acting on the object are F = (5.99 i + 14.98 j).

    (b) : The magnitude of the resultant force are F = 16.4 N < 68.19º.

    Explanation:

    m = 3kg

    a = 2 i + 5 j = 5.38 < 68.19 º

    F = m * a

    F = 3 * (5.38 < 68.19º)

    F = 16.4 N < 68.19º

    Fx = F * cos (68.19º)

    Fx = 5.99

    Fy = F * sin (68.19º)

    Fy = 14.98
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