Ask Question
12 March, 07:00

A child of mass 48.7 kg sits on the edge of a merry-go-round with radius 3 m and moment of inertia 376.938 kg m^2. The merry-go-round rotates with an angular velocity of 2.5 rad/s. What radial force does the child have to exert to stay on the merry-go-round? Answer in units of N.

+1
Answers (1)
  1. 12 March, 09:10
    0
    913.125 N

    Explanation:

    From the question,

    Applying

    Fc = mω²r ... Equation 1

    Where Fc = radial force of the child, m = mass of the child, ω = angular velocity, r = radius of the merry go round.

    Given: m = 48.7 kg, ω = 2.5 rad/s, r = 3 m

    Substitute into equation 1

    Fc = 48.7 (2.5²) (3)

    Fc = 48.7*6.25*3

    Fc = 913.125 N

    Hence the radial force the child have to exert to stay on the merry-go-round = 913.125 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A child of mass 48.7 kg sits on the edge of a merry-go-round with radius 3 m and moment of inertia 376.938 kg m^2. The merry-go-round ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers