An 80.0 kg man sits on a scale in his car. The car is driving at a speed of 11.0 m/s right as it passes over the top of a semicircular hill of radius 17.0 m. What does the scale read right when he is at the top

F / g = 138 kg

Explanation:

For this exercise let's use Newton's second law

F - W = m a

the force is equal to the back of the balance

in this case the acceleration is centripetal

a = v² / r

we substitute

F - m g = m v² / r

F = m (g + v² / r)

calculus

F = 80 (9.8 + 11²/17)

F = 1353 N

the balance reading is this value between gravity

F / g = 1353 / 9.8

F / g = 138 kg