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15 September, 01:53

How much heat does it take to raise the temperature of 7.0 kg of water from

25-C to 46-C? The specific heat of water is 4.18 kJ / (kg.-C).

Use Q = mcTr-T)

A. 148 kJ

B. 176 kJ

C. 610 kJ

D. 320 kJ

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Answers (1)
  1. 15 September, 04:08
    0
    non of the above

    Explanation:

    Quantity of heat = mass * specific heat * change in temperature

    m = 7kg c = 4.18 temp = 46-25=21°

    ... H = 7*4.18*21 = 614.46kJ
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