Ask Question
3 April, 08:26

José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without the riders falling. When the ride accelerates to a speed of 17.0 m/s, his angular momentum is 3570 kg m2/s. What is his mass?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits

+2
Answers (1)
  1. 3 April, 08:33
    0
    r = radius of the circle of the ride = 3.00 meters

    v = linear speed of the person during the ride = 17.0 m/s

    m = mass of the person in angular motion in the ride

    L = angular momentum of the person in the ride = 3570 kg m²/s

    Angular momentum is given as

    L = m v r

    inserting the values

    3570 kg m²/s = m (17 m/s) (3.00 m)

    m = 3570 kg m²/s / (51 m²/s)

    m = 7 kg

    hence the mass comes out to be 7 kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers