A man, a distance d=3~/text{m}d=3 m from a target, throws a ball at an angle / theta = 70^/circθ=70 ∘ above the horizontal. If the initial speed of the ball is v=5~/text{m/s}v=5 m/s, what height hh does the ball strike the building?

Question

Physics

Meyer

24 August, 08:58

A man, a distance d=3~/text{m}d=3 m from a target, throws a ball at an angle / theta = 70^/circθ=70 ∘ above the horizontal. If the initial speed of the ball is v=5~/text{m/s}v=5 m/s, what height hh does the ball strike the building?

+4

Answers (1)

Know the Answer?

Laci Moreno · Answer 1

The ball doesn't strike the building because it strikes the ground at d=1.62 meters.

Explanation:

V = 5 m/s < 70º

Vx = 1.71 m/s

Vy = 4.69 m/s

h = Vy * t - g * t²/2

clearing t for the flying time of the ball:

t = 0.95 s

d = Vx * t

d = 1.62 m