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15 March, 14:31

On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east. After traveling in a straight line for 2.13 km, they stop and discover that they have been traveling 25.9 ° north of east, because their guide misread his compass.

What are (a) the magnitude and (b) the direction (as a positive angle relative to due east) of the displacement vector now required to bring the team to the research station?

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  1. 15 March, 15:37
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    Exactly, it is a vector subtraction problem. Let t=theta,

    t1=38.7, d1=4.63; t2=25.9, d2=2.13

    v1=d1 =

    v2=d2 =

    Final vector

    v3 = v1-v2

    =

    =

    where

    v3x=d1*cos (t1) - d2*cos (t2)

    v3y=d1*sin (t1) - d2*sin (t2)

    The final vector v3 has therefore a magnitude of

    ||v3||=sqrt (1.6973^2+1.9645^2) = 2.5962, and a direction of

    theta=atan (1.9645/1.6973) = 49.17 degrees north of east

    Note: all three vectors are in the direction of the first quadrant.
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