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Today, 05:12

A wire carries a steady current of 2.20 A. A straight section of the wire is 0.750 m long and lies along the y axis within a uniform magnetic field, vector B = 1.70 k T. If the current is in the + y direction, what is the magnetic force on the section of wire?

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  1. Today, 08:53
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    2.805 N

    Explanation:

    Given,

    Current, I = 2.20 A

    Length of the section, L = 0.750 m

    Magnetic field, B = 1.70 T

    θ = 90°

    Magnetic Force, F = ?

    We know,

    F = IBL sin θ

    F = 2.20 x 1.70 x 0.750 x sin 90°

    F = 2.805 N

    Hence, magnetic force is equal to 2.805 N.
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