Ask Question
28 January, 12:27

A pump is partially submerged in oil and is supported by 4 springs. The oil has a specific gravity of 0.90, the weight of the pump is 14.6 lb, and the submerged volume is 40 in3. What force is needed in the springs so that the pump will remain in static equilibrium

+4
Answers (1)
  1. 28 January, 14:02
    0
    submerged volume of pump = 40 x 12⁻³ ft³

    density of oil =.9 x 62.4 lb ft⁻³ (specific gravity x density of water)

    mass of displaced oil = 40 x 12⁻³ x. 9 x 62.4 lb

    = 1.3 lb

    buoyant force = 1.3 lb

    weight of pump = 14.6 lb

    extra force needed for balancing pump by spring

    = 14.6 - 1.3

    = 13.3 lb.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A pump is partially submerged in oil and is supported by 4 springs. The oil has a specific gravity of 0.90, the weight of the pump is 14.6 ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers