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28 March, 01:56

The ballistic pendulum is an apparatus used to measure the speed of a projectile. An 8.0 g bullet is fired into a 2.5 kg ballistic pendulum bob, which is initially at rest, and becomes embedded in the bob. The pendulum then rises to a vertical distance of 6.0 cm. What was the initial speed of the bullet (in m/s) ?

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  1. 28 March, 03:32
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    1.242 m/s

    Explanation:

    Given that

    Mass of the bullet, m (b) = 8 kg.

    Mass of the pendulum, m (p) = 2.5 kg

    Height of the pendulum, h = 6 cm

    Initial speed of the bullet, v = ?

    Assuming that Energy is conserved, using law of conservation of energy, we have

    Potential Energy = Kinetic Energy

    mgh = 1/2mv²

    1/2mv² = [m (b) + m (p) ] gh

    1/2 * 8 * v² = (8 + 2.5) * 9.8 * 0.06

    4 v² = 10.5 * 0.588

    4 v² = 6.174

    v² = 6.174 / 4

    v² = 1.5435

    v = √1.5435

    v = 1.242 m/s

    Thus, the initial speed of the bullet is 1.242 m/s
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