A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 54 N or more. He is eager to get the fish to the dock in the shortest possible time. If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?

Question

Physics

Eric Gentry

10 March, 08:28

A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 54 N or more. He is eager to get the fish to the dock in the shortest possible time. If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?

+3

Answers (1)

Know the Answer?

Lee Shepard · Answer 1

The least amount of time in which the fisherman can raise the fish to the dock without losing it is t = 2 seconds.

Explanation:

m = 5 kg

h = 2m

Fmax = 54 N

g = 9.8 m/s²

W = m * g

W = 49 N

F = Fmax - W

F = 5 N

F=m*a

a = F/m

a = 1 m/s²

h = a * t²/2

t = √ (2*h/a)

t = 2 seconds