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6 April, 11:36

A 0.50kg object is at rest. A 3.00N force to the right acts on the objest during the time interval of 1.50s

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  1. 6 April, 13:14
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    The question you want to be answering is:

    What is the velocity of the object at the end of this interval?

    Key:

    M=0.5kg

    F=3N

    Δt = 1.5s

    Vi=0m/s

    Formula:

    F*Δt=m (Vf-Vi)

    Plug it in

    3 (1.5) = 0.5 (Vf-0)

    Solve for Vf

    4.5=0.5Vf

    Vf = 9 m/s
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