2. What is the magnitude of the force a 1.5 C charge exerts on a 3.2 C charge

located 1.5 m away?

The magnitude of the force is F=1.68*10 ^20 N

Explanation:

Given data

q1 = 1.5 10 ^6 q2=3.2 10^6 r=1.5

We have the formula

By the coulomb's law

F = K. q1 * q2 / r²

The K value is given by

8.99 10^9 Nm² / c²

substitute the values we get,

F = (8.99 * 10^9 Nm² / c²) * (1.5 * 10 ^6) * (3.2 * 10 ^6) / (1.6 m²)

F=1.68*10 ^20 N

The magnitude of the force is F=1.68*10 ^20 N