A particle moves along the x axis. Its position as function of time is given by x=6.8t+8.5t^2, where t is in seconds and x is in meters. What is the acceleration as a function of time?

Question

Physics

Eva Martin

4 December, 01:14

A particle moves along the x axis. Its position as function of time is given by x=6.8t+8.5t^2, where t is in seconds and x is in meters. What is the acceleration as a function of time?

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Answers (1)

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Layla Norris · Answer 1

Displacement=x-0=x (assuming the journey started at t=0)

time=t

x=ut+1/2 at^2

u=initial velocity=0

acceleration=a = ((x-ut) * 2) / t^2

a = (13.6t+17t^2) / t^2

a=17+13.6/t