The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Consider an RLC circuit with Epeak = 90 V, R = 28.9 capital omega, L = 1.31 H, and C = 2.86 µ F. Find the amplitude of the voltage across the inductor at resonance. V

Question

Physics

Dominik Freeman

13 February, 18:00

The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Consider an RLC circuit with Epeak = 90 V, R = 28.9 capital omega, L = 1.31 H, and C = 2.86 µ F. Find the amplitude of the voltage across the inductor at resonance. V

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Margaret Barry · Answer 1

VL=2107.6v

Explanation:

at resonance xc=xL

1/wc = wL

z=R

because sqr (R^2 + (xL-xc))

^

(xL=xc)

V/R=I

90/28.9=3.1142A

w=1/sqr (1.31 * (2.86*10^-6)) = 516.63

xL = wL

xL = 516.63*1.31=676.785

VL=3.1142*676.785

VL=2107.6v