In the study of sound, one version of the law of tensions is:

f1 = f2 √ (F1/F2)

If f1 = 300, F2 = 60, and f2=260, find f1 to the nearest unit.

Question

Physics

Sunshine

15 September, 03:31

In the study of sound, one version of the law of tensions is:

f1 = f2 √ (F1/F2)

If f1 = 300, F2 = 60, and f2=260, find f1 to the nearest unit.

+1

Answers (1)

Know the Answer?

Keenan Richardson · Answer 1

F1 = 80

Explanation:

f1 = f2 √ (F1/F2)

Where f1 = 300, f2 = 260 and F2 = 60

Putting in the above formula

300 = 260√ (F1/60)

Dividing both sides by 260

=> 1.15 = √ (F1/60)

Squaring both sides

=> 1.33 = F1/60

Multiplying both sides by 60

=> F1 = 80

In the study of sound, one version of the law of tensions is:f1 = f2 √ (F1/F2)If f1 = 300, F2 = 60, and f2=260, find f1 to the nearest unit.

In the study of sound, one version of the law of tensions is:

f1 = f2 √ (F1/F2)

If f1 = 300, F2 = 60, and f2=260, find f1 to the nearest unit.