3. A 40.0-kg wagon is towed up a hill inclined at 18.5 with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 140 N. Assume that the wagon starts from rest at the bottom of the hill, and neglect friction. How fast is the wagon going after moving 80.0 m up the hill?

Question

Aliana Diaz

5 July, 20:13

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Carlee Lucero · Answer 1

Force=tension-fg sin ∅

=140-mg sin 18.5

=140-124.35

=15.62N

a=f/m=15.62/40=0.39

now,

v²=u²+2as

=2*0.39*80

v²=62.4

v=7.8m/s