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24 January, 08:23

A transverse wave is traveling through a canal. If the distance between two successive crests is 2.37 m and four crests of the wave pass a buoy along the direction of travel every 22.6 s, determine the following.

(a) frequency of the wave. Hz

(b) speed at which the wave is traveling through the canal. m/s

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Answers (1)
  1. 24 January, 10:45
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    (a) 0.0885 Hz

    (b) 0.21 m/s

    Explanation:

    (a) Frequency: This can be defined as the number of cycle completed in one seconds.

    From the question,

    Note: 2 crest = one cycle,

    If four crest = 22.6 s,

    Then two crest = (22.6/2) s

    = 11.3 s.

    T = 11.3 s

    But,

    F = 1/T

    F = 1/11.3

    F = 0.0885 Hz.

    (b)

    Using,

    V = λF ... Equation 1

    Where V = speed of wave, F = Frequency of wave, λ = wave length.

    Given: F = 0.0885 Hz, λ = 2.37 m.

    Substitute these values into equation 1

    V = 2.37 (0.0885)

    V = 0.21 m/s.
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