If you weigh 665 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 18.0 km? Take the mass of the sun to be ms = 1.9910^30 kg, the gravitational constant to be G = 6.6710^-11 N⋅m2/kg^2, and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s^2.

Question

Physics

Carter Dougherty

1 September, 20:46

If you weigh 665 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 18.0 km? Take the mass of the sun to be ms = 1.9910^30 kg, the gravitational constant to be G = 6.6710^-11 N⋅m2/kg^2, and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s^2.

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Carlo Blankenship · Answer 1

1.113 x 10^14 N

Explanation:

Weight on earth = m ge = 665 N

mass = weight on earth / gravity on earth = 665 / 9.8 = 67.86 kg

The acceleration due to gravity on the planet is given by

g = GM / R^2

ms = 1.99 x 10^30 kg, G = 6.67 x 10^-11 Nm^2 / Kg^2, radius 9 km = 9000 m

so, the gravity on the planet

g = (6.67 x 10^-11 x 1.99 x 10^30) / (9000) ^2.

g = 1.64 x 10^12 m/s^2

So, weight on the planet = m x g

= 67.86 x 1.64 x 10^12 = 1.113 x 10^14 N