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17 March, 00:33

If the heat necessary to warm 565.0 g of water from a temperature of T1 = 22.0 °C to T2 = 80.0 °C were somehow converted to translational kinetic energy of this amount of water, what would be the speed of this water?

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  1. 17 March, 04:31
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    696.83 m/s

    Explanation:

    m = mass of water = 565 g = 0.565 kg

    c = specific heat of water = 4186 J / (kg⁰C)

    ΔT = Change in temperature = T₂ - T₁ = 80 - 22 = 58 ⁰C

    v = speed gained by water

    Using conservation of energy

    Kinetic energy gained by water = heat required to warm water

    (0.5) m v² = m c ΔT

    (0.5) v² = c ΔT

    (0.5) v² = (4186) (58)

    v = 696.83 m/s
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