A 15m long wire is placed horizontally on the surface of a liquid and is gently pulled up with the force of 60N to keep the wire in equilibrium. what is the surface tension of the liquid?

2 N/m

Explanation:

Given that

The length of a wire, l = 15 m

Force on the wire, F = 60 N

Surface tension on the liquid, S = ?

The formula to solve this problem is given as

F = S * 2 L, where

F = force on the liquid

S = surface tension of the liquid

L = length of the wire

On substituting the values of each, we have

60 = S * (2 * 15)

S = 60 / 30

S = 2 N/m

Thus, we can say then, that the surface tension of the liquid is 2 N/m