Three forces with magnitudes of 95 pounds, 75 pounds, and 146 pounds act on an object at angles 100°, 200°, and 300°, respectively, with the positive x-axis. Find the magnitude and direction of the resultant force. Round answers to two decimal places.

a. 41.84 pounds; 76.57degree

b. 60.18 pounds; 256.57degree

c. 60.18 pounds; 76.57degree

d. 41.84 pounds; 256.57degree

e. 81.89 pounds; 288.09degree

We shall represent all the forces in vector form.

Force of 95 pounds

F₁ = 95cos100 i + 95sin100j

= - 16.5 i + 93.55 j

force of 75 pounds

F₂ = 75cos200 + 75sin200j

= - 70.47 i - 25.65 j

force of 146 pounds

F₃ = 146cos300 i + 146sin300j

= 73i - 126.44 j

Resultant force

R = F₁ + F₂ + F₃

= - 16.5 i + 93.55 j - 70.47 i - 25.65 j + 73i - 126.44 j

= - 13.97 i - 58.54 j

Magnitude of R = √ (13.97² + 58.54²)

= 60.18

If Ф be angle of resultant with axis

tanФ = - 58.54 / - 13.97

Ф = 76.57 + 180 = 256.57, because both x and y components are negative. So the resultant will be in third quadrant.