A tire swing is released from some initial height such that the speed of the tire at the

bottom of the swing is 2.5 m/s. What is the initial height of the tire? Note: g = 9.8 m/s2

A 0.13m

B 0.16m

C 0.32m

D 3.1 m

The Initial height of the tire will be 0.32 m

Explanation:

We have the formula,

h=Vf^2/2g

h=V*f*f/2g

where Vf denotes the speed of the tire at the bottom of the swing

where g denotes the acceleration

due to the gravity

h=2.5*2.5=6.25

2*9.8 = 19.8

h=6.25/19.8

h=0.32

The Initial height of the tire will be 0.32 m