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20 January, 01:30

What is the de Broglie wavelength of a bullet of mass 0.030 kg traveling at 540 m/s? Planck's Constant is 6.63 * 10-34 J⋅s.

4.1 * 10-35 m

3.5 * 10-35 m

2.2 * 10-34 m

1.7 * 10-34 m

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Answers (1)
  1. 20 January, 03:12
    0
    I believe the answer is 4.1 * 10^-35 m

    Explanation:

    I worked out the problem using the equation for this kind of wavelength.

    Since I don't have the special keybind for it,? will be the wavelength.

    ? = h/p

    In this case, h = Planck's constant, which is 6.63 * 10^-34 J*s.

    P = momentum, which is mass * velocity.

    M (mass) = 0.030 kg.

    V (velocity) = 540 m/s.

    0.030 * 540 = 16.2.

    P = 16.2

    ? = h/p

    ? = (6.63 * 10^-34) / 16.2.

    ? = 4.0925 * 10^-35.

    ? = 4.1 * 10^-35.

    The wavelength is 4.1 * 10^-35 m.
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