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29 March, 21:46

A man uses a lever jack to lift a 2.00 x 10^3 kg car to change a tire. Each stroke of the jack lifts the car a distance of 5.00 x 10^-3 m. The vertical displacement of the handle is 0.75 m for each stroke. How much total force does he use with each stroke of the jack?

A) 19,600 N

B) 3.0 x 10^5 N

C) 131 N

D) 2.9 x 10^6 N

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Answers (1)
  1. 29 March, 23:26
    0
    Convert weight to Newtons:

    2 * 10^3 * 9.81 = 19.62*10^3 N

    Find the mechanical advantage of the handle:

    .75/.005 = 150

    Now divide the weight in Newtons, by the mechanical advantage:

    (19.62/150) * 10^3 = 130.8 N

    Round to 131 N

    The answer is C.
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