The equation of trajectory of a projectile is y=10x - (5/9) x^2 if we assume g=10m/s^2, the range of projectile in meters is?

Question

Physics

Orion Arnold

23 March, 13:29

The equation of trajectory of a projectile is y=10x - (5/9) x^2 if we assume g=10m/s^2, the range of projectile in meters is?

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Answers (1)

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Naima Parsons · Answer 1

18 m

Explanation:

y = 10x - 5/9 x²

When the projectile lands, y=0:

0 = 10x - 5/9 x²

0 = x (10 - 5/9 x)

x = 0, 18

The range of the projectile is 18 m.