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Today, 14:08

calculate the force exerted on a rocket given that the propelling gases are expelled at a rate of 1500 kg/s with a speed of 4.0x10^4 (at the moment of take off)

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  1. Today, 16:47
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    we know that momentum is given as

    P = mv

    where P = momentum, m = mass, v = velocity

    taking derivative both side relative to "t"

    dP/dt = v (dm/dt)

    we know that : dP/dt = F = force

    hence

    F = v (dm/dt)

    given that:

    dm/dt = rate of mass expelled = 1500 kg/s

    v = velocity = 4 x 10⁴ m/s

    hence, inserting the values in the above formula

    F = (4 x 10⁴) (1500)

    F = 6 x 10⁷ N
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