A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / (g ° C) 0.123 J / (g°C), what is the change in temperature of the sample?

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J / (g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J / (g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J / 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C