What average net force is required to accelerate a 9.5 g

bullet from rest to 650 m/s over a distance of 0.85 m along the

barrel of a rifle?

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² : 2s

= 650² : 2 (0.85)

= 248,529.40 m/s²

But;

F = ma

= 0.0095 kg * 248,529.40 m/s²

= 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.