Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of 10 cm/s and does not slip on the tube, the angular velocity of the tube is:

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Physics

Blackburn

3 July, 05:16

Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of 10 cm/s and does not slip on the tube, the angular velocity of the tube is:

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Twinkly · Answer 1

So the equation for angular velocity is

Omega = 2 (3.14) / T

Where T is the total period in which the cylinder completes one revolution.

In order to find T, the tangential velocity is

V = 2 (3.14) r/T

When calculated, I got V = 3.14

When you enter that into the angular velocity equation, you should get 2m/s