A golfer strikes a stationary golf ball that has a mass of 0.02 kg. The golf ball leaves the club with a speed of 180 m/s. A high-speed camera determines that the club was in contact with the ball for 0.56 x 10-3 s. What was the average force applied by the club to the ball in newtons

Answer

The average force applied by the club to the ball in Newtons is 6428.5N

Explanation:

Step one:

Given data

Mass of golf ball = 0.02kg

Velocity of the ball = 180m/s

Time = 0.56*10-³s

Step two:

We know that the impulse equation is given by

P*t=m*v

Where p = impulse in Newton?

t=time in seconds

m = mass in kg

v = velocity in m/s

Step three

To find the average force applied we Substitute our data into the equation we have

P*0.56*10-³=0.02*180

P=3.6/0.56*10-³

P=6428.5N