Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 * 10-19 C and Coulomb's constant is 8.987 * 109 N · m2/C2. Answer in units of m.

The answer to your question is distance between these electrons

= 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

F = kq₁q₂ / r²

-Solve for r²

r² = kq₁q₂ / F

-Substitution

r² = (8.987 x 10⁹) (1.602 x 10⁻¹⁹) (1.602 x 10⁻¹⁹) / 1.2

- Simplification

r² = 2.306 x 10⁻²⁸ / 1.2

r² = 1.922 x 10⁻²⁸

-Result

r = 1.386 x 10⁻¹⁴ m