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1 February, 06:17

Q27) A racing car can be slowed with a deceleration of - 11 m/s?. If it is moving with 55 m/s how for

will it travel to stop, express your answer in scientific notation?

a) 2.4 x10 m

b) 4.1 x10 m

C) 1.4

102 m

d) 3.2 10m

+3
Answers (1)
  1. P
    1 February, 07:51
    0
    C

    Explanation:

    We know, v^2 = u^2 + 2as

    Putting in the values, we get,

    0^2 = 55^2 + (2 * (-11) * s)

    22s = 3025

    s = 137.5 = 1.375 * 10^2 ≈ 1.4 * 10^2
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