A bottle rocket takes off with a = 34.5 m/s2. It

fires until it reaches a height of 200 m, then

shuts off, and gravity takes over. How much

time does it take to reach its maximum height?

(Unit = s)

Answer:3.4 seconds

Explanation:

Initial velocity (u) = 0

acceleration=34.5m/s^2

Height (h) = 200m

Time = t

h=u x t - (gxt^2) / 2

200=0xt + (34.5xt^2) / 2

200=34.5t^2/2

Cross multiply

200x2=34.5t^2

400=34.5t^2

Divide both sides by 34.5

400/34.5=34.5t^2/34.5

11.59=t^2

t^2=11.59

Take them square root of both sides

t=√ (11.59)

t=3.4 seconds