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5 November, 01:56

Convert the acceleration of a free falling body 9.8 m/s^2 to ft/s^2

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Answers (2)
  1. 5 November, 03:19
    0
    hoping this is the right answer : Use A = log (100/%T) = 2.0 - log %T

    a) A = 2.00 - log 53.86 = 2.00 - 1.73 = 0.27

    b) A = 2.00 - log 0.56 = 2.00 + 0.25 = 2.25

    i feel like ur going to delete this but i tried
  2. 5 November, 03:38
    0
    i hoping this is the right answer : Use A = log (100/%T) = 2.0 - log %T

    a) A = 2.00 - log 53.86 = 2.00 - 1.73 = 0.27

    b) A = 2.00 - log 0.56 = 2.00 + 0.25 = 2.25

    i feel like ur going to delete this but i tried
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